# Line slope calculator x-5y=-10

**Straight line given by points A[0; 2] and B[5; 3]**

## Calculation:

**Slope-intercept form of line:**y = 0.2x+2

**Canonical form of the line equation:**x-5y+10 = 0

**Parametric form of the line equation:**

x = 5t

y = t+2 ; t ∈ R

**Slope:**m = 0.2

**Slope angle of line: φ =**11°18'36″ = 0.1974 rad

**X intercept:**x

_{0}= -10

**Y intercept:**y

_{0}= q = 2

**Distance line from the origin:**d

_{0}= 1.9612

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; 1)

**Normal vector: n =**(1; -5)

**Midpoint of the segment AB: M =**[2.5; 2.5]

**Perpendicular Bisector equation:**5x+y-15 = 0

**Vector OA = (0; 2) ; |OA| = 2**

**Vector OB = (5; 3) ; |OB| = 5.831**

**Scalar product OA .OB = 6**

**Angle ∠ AOB = 59°2'10″ = 1.0304 rad**